Metamath Proof Explorer


Theorem prlngpln4

Description: Building a parallel line conserves planes, i.e. given a line A and a point X not on A , the (unique) parallel B to A through X lies completely within the plane defined by A and X . Theorem 12.14 of Schwabhauser p. 124. (Contributed by Thierry Arnoux, 13-Jul-2026)

Ref Expression
Hypotheses prlngpln4.e No typesetting found for |- E = ( PlnG ` G ) with typecode |-
prlngpln4.p No typesetting found for |- .|| = ( parlnG ` G ) with typecode |-
prlngpln4.g φ G 𝒢 Tarski
prlngpln4.h φ H ran E
prlngpln4.a φ A H
prlngpln4.1 φ A ˙ B
prlngpln4.x φ X H
prlngpln4.2 φ X B
Assertion prlngpln4 φ B H

Proof

Step Hyp Ref Expression
1 prlngpln4.e Could not format E = ( PlnG ` G ) : No typesetting found for |- E = ( PlnG ` G ) with typecode |-
2 prlngpln4.p Could not format .|| = ( parlnG ` G ) : No typesetting found for |- .|| = ( parlnG ` G ) with typecode |-
3 prlngpln4.g φ G 𝒢 Tarski
4 prlngpln4.h φ H ran E
5 prlngpln4.a φ A H
6 prlngpln4.1 φ A ˙ B
7 prlngpln4.x φ X H
8 prlngpln4.2 φ X B
9 simpr φ A = B A = B
10 5 adantr φ A = B A H
11 9 10 eqsstrrd φ A = B B H
12 eqid Line 𝒢 G = Line 𝒢 G
13 3 adantr φ A B G 𝒢 Tarski
14 6 adantr φ A B A ˙ B
15 simpr φ A B A B
16 8 adantr φ A B X B
17 12 1 2 13 14 15 16 prlngpln3 φ A B B A E X
18 eqid Base G = Base G
19 4 adantr φ A B H ran E
20 12 2 3 6 prlngrcl1 φ A ran Line 𝒢 G
21 20 adantr φ A B A ran Line 𝒢 G
22 7 adantr φ A B X H
23 12 2 13 14 15 prlngin0 φ A B A B =
24 23 adantr φ A B X A A B =
25 simpr φ A B X A X A
26 8 ad2antrr φ A B X A X B
27 25 26 elind φ A B X A X A B
28 27 ne0d φ A B X A A B
29 28 neneqd φ A B X A ¬ A B =
30 24 29 pm2.65da φ A B ¬ X A
31 22 30 eldifd φ A B X H A
32 5 adantr φ A B A H
33 18 12 1 13 19 21 31 32 plng3p φ A B H = A E X
34 17 33 sseqtrrd φ A B B H
35 11 34 pm2.61dane φ B H