Metamath Proof Explorer


Theorem prodeq2sdv

Description: Equality deduction for product. (Contributed by Scott Fenton, 4-Dec-2017)

Ref Expression
Hypothesis prodeq2sdv.1 φB=C
Assertion prodeq2sdv φkAB=kAC

Proof

Step Hyp Ref Expression
1 prodeq2sdv.1 φB=C
2 1 adantr φkAB=C
3 2 prodeq2dv φkAB=kAC