Theorem rbaibr

Description: Move conjunction outside of biconditional. (Contributed by Mario Carneiro, 11-Sep-2015) (Proof shortened by Wolf Lammen, 19-Jan-2020)

	Ref	Expression
Hypothesis	baib.1	$$⊢\phi \leftrightarrow \left(\psi \wedge \chi \right)$$
Assertion	rbaibr	$$⊢\chi \to \left(\psi \leftrightarrow \phi \right)$$

Proof

Step	Hyp	Ref	Expression
1		baib.1	$$⊢\phi \leftrightarrow \left(\psi \wedge \chi \right)$$
2	1	biancomi	$$⊢\phi \leftrightarrow \left(\chi \wedge \psi \right)$$
3	2	baibr	$$⊢\chi \to \left(\psi \leftrightarrow \phi \right)$$