Metamath Proof Explorer


Theorem recdiv

Description: The reciprocal of a ratio. (Contributed by NM, 3-Aug-2004)

Ref Expression
Assertion recdiv ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ B ∈ ℂ ∧ B ≠ 0 → 1 A B = B A

Proof

Step Hyp Ref Expression
1 1div1e1 ⊢ 1 1 = 1
2 1 oveq1i ⊢ 1 1 A B = 1 A B
3 ax-1cn ⊢ 1 ∈ ℂ
4 ax-1ne0 ⊢ 1 ≠ 0
5 3 4 pm3.2i ⊢ 1 ∈ ℂ ∧ 1 ≠ 0
6 divdivdiv ⊢ 1 ∈ ℂ ∧ 1 ∈ ℂ ∧ 1 ≠ 0 ∧ A ∈ ℂ ∧ A ≠ 0 ∧ B ∈ ℂ ∧ B ≠ 0 → 1 1 A B = 1 ⁢ B 1 ⁢ A
7 3 5 6 mpanl12 ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ B ∈ ℂ ∧ B ≠ 0 → 1 1 A B = 1 ⁢ B 1 ⁢ A
8 2 7 eqtr3id ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ B ∈ ℂ ∧ B ≠ 0 → 1 A B = 1 ⁢ B 1 ⁢ A
9 mullid ⊢ B ∈ ℂ → 1 ⁢ B = B
10 mullid ⊢ A ∈ ℂ → 1 ⁢ A = A
11 9 10 oveqan12rd ⊢ A ∈ ℂ ∧ B ∈ ℂ → 1 ⁢ B 1 ⁢ A = B A
12 11 ad2ant2r ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ B ∈ ℂ ∧ B ≠ 0 → 1 ⁢ B 1 ⁢ A = B A
13 8 12 eqtrd ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ B ∈ ℂ ∧ B ≠ 0 → 1 A B = B A