Metamath Proof Explorer


Theorem releq

Description: Equality theorem for the relation predicate. (Contributed by NM, 1-Aug-1994)

Ref Expression
Assertion releq ⊢ A = B → Rel ⁡ A ↔ Rel ⁡ B

Proof

Step Hyp Ref Expression
1 sseq1 ⊢ A = B → A ⊆ V × V ↔ B ⊆ V × V
2 df-rel ⊢ Rel ⁡ A ↔ A ⊆ V × V
3 df-rel ⊢ Rel ⁡ B ↔ B ⊆ V × V
4 1 2 3 3bitr4g ⊢ A = B → Rel ⁡ A ↔ Rel ⁡ B