Metamath Proof Explorer


Theorem releqi

Description: Equality inference for the relation predicate. (Contributed by NM, 8-Dec-2006)

Ref Expression
Hypothesis releqi.1 ⊢ A = B
Assertion releqi ⊢ Rel ⁡ A ↔ Rel ⁡ B

Proof

Step Hyp Ref Expression
1 releqi.1 ⊢ A = B
2 releq ⊢ A = B → Rel ⁡ A ↔ Rel ⁡ B
3 1 2 ax-mp ⊢ Rel ⁡ A ↔ Rel ⁡ B