Metamath Proof Explorer


Theorem reseccl

Description: The closure of the secant function with a real argument. (Contributed by David A. Wheeler, 15-Mar-2014)

Ref Expression
Assertion reseccl ⊢ A ∈ ℝ ∧ cos ⁡ A ≠ 0 → sec ⁡ A ∈ ℝ

Proof

Step Hyp Ref Expression
1 recn ⊢ A ∈ ℝ → A ∈ ℂ
2 secval ⊢ A ∈ ℂ ∧ cos ⁡ A ≠ 0 → sec ⁡ A = 1 cos ⁡ A
3 1 2 sylan ⊢ A ∈ ℝ ∧ cos ⁡ A ≠ 0 → sec ⁡ A = 1 cos ⁡ A
4 recoscl ⊢ A ∈ ℝ → cos ⁡ A ∈ ℝ
5 1red ⊢ A ∈ ℝ → 1 ∈ ℝ
6 redivcl ⊢ 1 ∈ ℝ ∧ cos ⁡ A ∈ ℝ ∧ cos ⁡ A ≠ 0 → 1 cos ⁡ A ∈ ℝ
7 5 6 syl3an1 ⊢ A ∈ ℝ ∧ cos ⁡ A ∈ ℝ ∧ cos ⁡ A ≠ 0 → 1 cos ⁡ A ∈ ℝ
8 4 7 syl3an2 ⊢ A ∈ ℝ ∧ A ∈ ℝ ∧ cos ⁡ A ≠ 0 → 1 cos ⁡ A ∈ ℝ
9 8 3anidm12 ⊢ A ∈ ℝ ∧ cos ⁡ A ≠ 0 → 1 cos ⁡ A ∈ ℝ
10 3 9 eqeltrd ⊢ A ∈ ℝ ∧ cos ⁡ A ≠ 0 → sec ⁡ A ∈ ℝ