Metamath Proof Explorer


Theorem rimf1o

Description: An isomorphism of rings is a bijection. (Contributed by Jeff Madsen, 16-Jun-2011) (Revised by AV, 22-Oct-2019)

Ref Expression
Hypotheses rhmf1o.b ⊢ B = Base R
rhmf1o.c ⊢ C = Base S
Assertion rimf1o ⊢ F ∈ R RingIso S → F : B ⟶ 1-1 onto C

Proof

Step Hyp Ref Expression
1 rhmf1o.b ⊢ B = Base R
2 rhmf1o.c ⊢ C = Base S
3 1 2 isrim ⊢ F ∈ R RingIso S ↔ F ∈ R RingHom S ∧ F : B ⟶ 1-1 onto C
4 3 simprbi ⊢ F ∈ R RingIso S → F : B ⟶ 1-1 onto C