Metamath Proof Explorer


Theorem sbcfal

Description: Substituting a class in the false truth constant results in the false truth constant. The analogous result with the true truth constant does not hold in general since substituting a proper class results in falsehood ( sbcex ), but holds for sets by sbcg . (Contributed by BJ, 11-Oct-2026)

Ref Expression
Assertion sbcfal ⊢ [˙A / x]˙ ⊥ ↔ ⊥

Proof

Step Hyp Ref Expression
1 sbcex ⊢ [˙A / x]˙ ⊥ → A ∈ V
2 falim ⊢ ⊥ → A ∈ V
3 sbcg ⊢ A ∈ V → [˙A / x]˙ ⊥ ↔ ⊥
4 1 2 3 pm5.21nii ⊢ [˙A / x]˙ ⊥ ↔ ⊥