Metamath Proof Explorer


Theorem sbcfal

Description: Substituting a class in the false truth constant results in the false truth constant. The analogous result with the true truth constant does not hold in general since substituting a proper class results in falsehood ( sbcex ), but holds for sets by sbcg . (Contributed by BJ, 11-Oct-2026)

Ref Expression
Assertion sbcfal
|- ( [. A / x ]. F. <-> F. )

Proof

Step Hyp Ref Expression
1 sbcex
 |-  ( [. A / x ]. F. -> A e. _V )
2 falim
 |-  ( F. -> A e. _V )
3 sbcg
 |-  ( A e. _V -> ( [. A / x ]. F. <-> F. ) )
4 1 2 3 pm5.21nii
 |-  ( [. A / x ]. F. <-> F. )