Metamath Proof Explorer


Theorem sbcfal

Description: Substituting a class in the false truth constant results in the false truth constant. The analogous result with the true truth constant does not hold in general since substituting a proper class results in falsehood ( sbcex ), but holds for sets by sbcg . (Contributed by BJ, 11-Oct-2026)

Ref Expression
Assertion sbcfal ( [ 𝐴 / 𝑥 ] ⊥ ↔ ⊥ )

Proof

Step Hyp Ref Expression
1 sbcex ⊢ ( [ 𝐴 / 𝑥 ] ⊥ → 𝐴 ∈ V )
2 falim ⊢ ( ⊥ → 𝐴 ∈ V )
3 sbcg ⊢ ( 𝐴 ∈ V → ( [ 𝐴 / 𝑥 ] ⊥ ↔ ⊥ ) )
4 1 2 3 pm5.21nii ⊢ ( [ 𝐴 / 𝑥 ] ⊥ ↔ ⊥ )