Metamath Proof Explorer
Description: Eliminate an antecedent implied by each side of a biconditional.
(Contributed by NM, 21-May-1999)
|
|
Ref |
Expression |
|
Hypotheses |
pm5.21ni.1 |
⊢ ( 𝜑 → 𝜓 ) |
|
|
pm5.21ni.2 |
⊢ ( 𝜒 → 𝜓 ) |
|
|
pm5.21nii.3 |
⊢ ( 𝜓 → ( 𝜑 ↔ 𝜒 ) ) |
|
Assertion |
pm5.21nii |
⊢ ( 𝜑 ↔ 𝜒 ) |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
pm5.21ni.1 |
⊢ ( 𝜑 → 𝜓 ) |
| 2 |
|
pm5.21ni.2 |
⊢ ( 𝜒 → 𝜓 ) |
| 3 |
|
pm5.21nii.3 |
⊢ ( 𝜓 → ( 𝜑 ↔ 𝜒 ) ) |
| 4 |
1 2
|
pm5.21ni |
⊢ ( ¬ 𝜓 → ( 𝜑 ↔ 𝜒 ) ) |
| 5 |
3 4
|
pm2.61i |
⊢ ( 𝜑 ↔ 𝜒 ) |