Metamath Proof Explorer


Theorem sbcg

Description: Substitution for a variable not occurring in a wff does not affect it. Distinct variable form of sbcgf . (Contributed by Alan Sare, 10-Nov-2012)

Ref Expression
Assertion sbcg
|- ( A e. V -> ( [. A / x ]. ph <-> ph ) )

Proof

Step Hyp Ref Expression
1 nfv
 |-  F/ x ph
2 1 sbcgf
 |-  ( A e. V -> ( [. A / x ]. ph <-> ph ) )