Metamath Proof Explorer
		
		
		
		Description:  An equality theorem for substitution.  (Contributed by NM, 6-Oct-2004)
     (Proof shortened by Andrew Salmon, 21-Jun-2011)
		
			
				
					|  |  | Ref | Expression | 
				
					|  | Assertion | sbequ12r |  | 
			
		
		
			
				Proof
				
					
						| Step | Hyp | Ref | Expression | 
						
							| 1 |  | sbequ12 |  | 
						
							| 2 | 1 | bicomd |  | 
						
							| 3 | 2 | equcoms |  |