Metamath Proof Explorer


Theorem sconnpconn

Description: A simply connected space is path-connected. (Contributed by Mario Carneiro, 11-Feb-2015)

Ref Expression
Assertion sconnpconn ⊢ J ∈ SConn → J ∈ PConn

Proof

Step Hyp Ref Expression
1 issconn ⊢ J ∈ SConn ↔ J ∈ PConn ∧ ∀ f ∈ II Cn J f ⁡ 0 = f ⁡ 1 → f ≃ ph ⁡ J 0 1 × f ⁡ 0
2 1 simplbi ⊢ J ∈ SConn → J ∈ PConn