Metamath Proof Explorer


Theorem sconnpconn

Description: A simply connected space is path-connected. (Contributed by Mario Carneiro, 11-Feb-2015)

Ref Expression
Assertion sconnpconn ( 𝐽 ∈ SConn → 𝐽 ∈ PConn )

Proof

Step Hyp Ref Expression
1 issconn ( 𝐽 ∈ SConn ↔ ( 𝐽 ∈ PConn ∧ ∀ 𝑓 ∈ ( II Cn 𝐽 ) ( ( 𝑓 ‘ 0 ) = ( 𝑓 ‘ 1 ) → 𝑓 ( ≃ph𝐽 ) ( ( 0 [,] 1 ) × { ( 𝑓 ‘ 0 ) } ) ) ) )
2 1 simplbi ( 𝐽 ∈ SConn → 𝐽 ∈ PConn )