Metamath Proof Explorer


Theorem scott0bOLD

Description: Obsolete version of scott0b as of 18-Jul-2026. (Contributed by BTernaryTau, 3-Jul-2026) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion scott0bOLD ⊢ A = ∅ ↔ Scott A = ∅

Proof

Step Hyp Ref Expression
1 scott0OLD ⊢ A = ∅ ↔ x ∈ A | ∀ y ∈ A rank ⁡ x ⊆ rank ⁡ y = ∅
2 df-scott ⊢ Scott A = x ∈ A | ∀ y ∈ A rank ⁡ x ⊆ rank ⁡ y
3 2 eqeq1i ⊢ Scott A = ∅ ↔ x ∈ A | ∀ y ∈ A rank ⁡ x ⊆ rank ⁡ y = ∅
4 1 3 bitr4i ⊢ A = ∅ ↔ Scott A = ∅