Metamath Proof Explorer


Theorem scottabes

Description: Value of the Scott operation at a class abstraction. Variant of scottab using explicit substitution. (Contributed by Rohan Ridenour, 14-Aug-2023)

Ref Expression
Assertion scottabes ⊢ Scott x | φ = x | φ ∧ ∀ y y x φ → rank ⁡ x ⊆ rank ⁡ y

Proof

Step Hyp Ref Expression
1 nfs1v ⊢ Ⅎ x y x φ
2 sbequ12 ⊢ x = y → φ ↔ y x φ
3 1 2 scottabf ⊢ Scott x | φ = x | φ ∧ ∀ y y x φ → rank ⁡ x ⊆ rank ⁡ y