Metamath Proof Explorer


Theorem seeq2

Description: Equality theorem for the set-like predicate. (Contributed by Mario Carneiro, 24-Jun-2015)

Ref Expression
Assertion seeq2 ⊢ A = B → R Se A ↔ R Se B

Proof

Step Hyp Ref Expression
1 eqimss2 ⊢ A = B → B ⊆ A
2 sess2 ⊢ B ⊆ A → R Se A → R Se B
3 1 2 syl ⊢ A = B → R Se A → R Se B
4 eqimss ⊢ A = B → A ⊆ B
5 sess2 ⊢ A ⊆ B → R Se B → R Se A
6 4 5 syl ⊢ A = B → R Se B → R Se A
7 3 6 impbid ⊢ A = B → R Se A ↔ R Se B