Metamath Proof Explorer


Theorem seeq12d

Description: Equality deduction for the set-like predicate. (Contributed by Matthew House, 10-Sep-2025)

Ref Expression
Hypotheses seeq12d.1 ⊢ φ → R = S
seeq12d.2 ⊢ φ → A = B
Assertion seeq12d ⊢ φ → R Se A ↔ S Se B

Proof

Step Hyp Ref Expression
1 seeq12d.1 ⊢ φ → R = S
2 seeq12d.2 ⊢ φ → A = B
3 seeq1 ⊢ R = S → R Se A ↔ S Se A
4 seeq2 ⊢ A = B → S Se A ↔ S Se B
5 3 4 sylan9bb ⊢ R = S ∧ A = B → R Se A ↔ S Se B
6 1 2 5 syl2anc ⊢ φ → R Se A ↔ S Se B