Metamath Proof Explorer


Theorem sibfrn

Description: A simple function has finite range. (Contributed by Thierry Arnoux, 19-Feb-2018)

Ref Expression
Hypotheses sitgval.b ⊢ B = Base W
sitgval.j ⊢ J = TopOpen ⁡ W
sitgval.s ⊢ S = 𝛔 ⁡ J
sitgval.0 ⊢ 0 ˙ = 0 W
sitgval.x ⊢ · ˙ = ⋅ W
sitgval.h ⊢ H = ℝHom ⁡ Scalar ⁡ W
sitgval.1 ⊢ φ → W ∈ V
sitgval.2 ⊢ φ → M ∈ ⋃ ran ⁡ measures
sibfmbl.1 ⊢ φ → F ∈ ℑ M W
Assertion sibfrn ⊢ φ → ran ⁡ F ∈ Fin

Proof

Step Hyp Ref Expression
1 sitgval.b ⊢ B = Base W
2 sitgval.j ⊢ J = TopOpen ⁡ W
3 sitgval.s ⊢ S = 𝛔 ⁡ J
4 sitgval.0 ⊢ 0 ˙ = 0 W
5 sitgval.x ⊢ · ˙ = ⋅ W
6 sitgval.h ⊢ H = ℝHom ⁡ Scalar ⁡ W
7 sitgval.1 ⊢ φ → W ∈ V
8 sitgval.2 ⊢ φ → M ∈ ⋃ ran ⁡ measures
9 sibfmbl.1 ⊢ φ → F ∈ ℑ M W
10 1 2 3 4 5 6 7 8 issibf ⊢ φ → F ∈ ℑ M W ↔ F ∈ dom ⁡ M MblFn μ S ∧ ran ⁡ F ∈ Fin ∧ ∀ x ∈ ran ⁡ F ∖ 0 ˙ M ⁡ F -1 x ∈ 0 +∞
11 9 10 mpbid ⊢ φ → F ∈ dom ⁡ M MblFn μ S ∧ ran ⁡ F ∈ Fin ∧ ∀ x ∈ ran ⁡ F ∖ 0 ˙ M ⁡ F -1 x ∈ 0 +∞
12 11 simp2d ⊢ φ → ran ⁡ F ∈ Fin