Metamath Proof Explorer


Theorem simplld

Description: Deduction form of simpll , eliminating a double conjunct. (Contributed by Glauco Siliprandi, 11-Dec-2019)

Ref Expression
Hypothesis simplld.1 ⊢ φ → ψ ∧ χ ∧ θ
Assertion simplld ⊢ φ → ψ

Proof

Step Hyp Ref Expression
1 simplld.1 ⊢ φ → ψ ∧ χ ∧ θ
2 1 simpld ⊢ φ → ψ ∧ χ
3 2 simpld ⊢ φ → ψ