Metamath Proof Explorer

Theorem simpr1r

Description: Simplification of conjunction. (Contributed by NM, 9-Mar-2012) (Proof shortened by Wolf Lammen, 24-Jun-2022)

		Ref	Expression
	Assertion	simpr1r	$⊢ (τ \land ((φ \land ψ) \land χ \land θ)) \to ψ$

Step	Hyp	Ref	Expression
1		simprr	$⊢ (τ \land (φ \land ψ)) \to ψ$
2	1	3ad2antr1	$⊢ (τ \land ((φ \land ψ) \land χ \land θ)) \to ψ$