Metamath Proof Explorer


Theorem spcegv

Description: Existential specialization, using implicit substitution. (Contributed by NM, 14-Aug-1994) Avoid ax-10 , ax-11 . (Revised by Wolf Lammen, 25-Aug-2023)

Ref Expression
Hypothesis spcgv.1 ⊢ x = A → φ ↔ ψ
Assertion spcegv ⊢ A ∈ V → ψ → ∃ x φ

Proof

Step Hyp Ref Expression
1 spcgv.1 ⊢ x = A → φ ↔ ψ
2 elisset ⊢ A ∈ V → ∃ x x = A
3 1 biimprcd ⊢ ψ → x = A → φ
4 3 eximdv ⊢ ψ → ∃ x x = A → ∃ x φ
5 2 4 syl5com ⊢ A ∈ V → ψ → ∃ x φ