Metamath Proof Explorer


Theorem spsbeOLD

Description: Obsolete version of spsbe as of 11-Jul-2023. (Contributed by NM, 29-Jun-1993) (Proof shortened by Wolf Lammen, 3-May-2018) Revise df-sb . (Revised by BJ, 22-Dec-2020) (New usage is discouraged.) (Proof modification is discouraged.)

Ref Expression
Assertion spsbeOLD t x φ x φ

Proof

Step Hyp Ref Expression
1 df-sb t x φ y y = t x x = y φ
2 ax6ev y y = t
3 exim y y = t x x = y φ y y = t y x x = y φ
4 2 3 mpi y y = t x x = y φ y x x = y φ
5 1 4 sylbi t x φ y x x = y φ
6 exim x x = y φ x x = y x φ
7 6 eximi y x x = y φ y x x = y x φ
8 ax6ev x x = y
9 pm2.27 x x = y x x = y x φ x φ
10 8 9 ax-mp x x = y x φ x φ
11 10 exlimiv y x x = y x φ x φ
12 5 7 11 3syl t x φ x φ