Metamath Proof Explorer


Theorem sq0

Description: The square of 0 is 0. (Contributed by NM, 6-Jun-2006)

Ref Expression
Assertion sq0 02=0

Proof

Step Hyp Ref Expression
1 eqid 0=0
2 0cn 0
3 2 sqeq0i 02=00=0
4 1 3 mpbir 02=0