Metamath Proof Explorer


Theorem sq4e2t8

Description: The square of 4 is 2 times 8. (Contributed by AV, 20-Jul-2021)

Ref Expression
Assertion sq4e2t8 ⊢ 4 2 = 2 ⋅ 8

Proof

Step Hyp Ref Expression
1 2t2e4 ⊢ 2 ⋅ 2 = 4
2 1 eqcomi ⊢ 4 = 2 ⋅ 2
3 2 oveq1i ⊢ 4 2 = 2 ⋅ 2 2
4 2cn ⊢ 2 ∈ ℂ
5 4 4 sqmuli ⊢ 2 ⋅ 2 2 = 2 2 ⁢ 2 2
6 4 sqvali ⊢ 2 2 = 2 ⋅ 2
7 sq2 ⊢ 2 2 = 4
8 6 7 oveq12i ⊢ 2 2 ⁢ 2 2 = 2 ⋅ 2 ⋅ 4
9 4cn ⊢ 4 ∈ ℂ
10 4 4 9 mulassi ⊢ 2 ⋅ 2 ⋅ 4 = 2 ⁢ 2 ⋅ 4
11 2t4e8 ⊢ 2 ⋅ 4 = 8
12 11 oveq2i ⊢ 2 ⁢ 2 ⋅ 4 = 2 ⋅ 8
13 8 10 12 3eqtri ⊢ 2 2 ⁢ 2 2 = 2 ⋅ 8
14 3 5 13 3eqtri ⊢ 4 2 = 2 ⋅ 8