Metamath Proof Explorer


Theorem sseqtri

Description: Substitution of equality into a subclass relationship. (Contributed by NM, 28-Jul-1995)

Ref Expression
Hypotheses sseqtr.1 ⊢ A ⊆ B
sseqtr.2 ⊢ B = C
Assertion sseqtri ⊢ A ⊆ C

Proof

Step Hyp Ref Expression
1 sseqtr.1 ⊢ A ⊆ B
2 sseqtr.2 ⊢ B = C
3 2 sseq2i ⊢ A ⊆ B ↔ A ⊆ C
4 1 3 mpbi ⊢ A ⊆ C