Metamath Proof Explorer


Theorem ssoprab2i

Description: Inference of operation class abstraction subclass from implication. (Contributed by NM, 11-Nov-1995) (Revised by David Abernethy, 19-Jun-2012)

Ref Expression
Hypothesis ssoprab2i.1 ⊢ φ → ψ
Assertion ssoprab2i ⊢ x y z | φ ⊆ x y z | ψ

Proof

Step Hyp Ref Expression
1 ssoprab2i.1 ⊢ φ → ψ
2 1 anim2i ⊢ w = x y ∧ φ → w = x y ∧ ψ
3 2 2eximi ⊢ ∃ x ∃ y w = x y ∧ φ → ∃ x ∃ y w = x y ∧ ψ
4 3 ssopab2i ⊢ w z | ∃ x ∃ y w = x y ∧ φ ⊆ w z | ∃ x ∃ y w = x y ∧ ψ
5 dfoprab2 ⊢ x y z | φ = w z | ∃ x ∃ y w = x y ∧ φ
6 dfoprab2 ⊢ x y z | ψ = w z | ∃ x ∃ y w = x y ∧ ψ
7 4 5 6 3sstr4i ⊢ x y z | φ ⊆ x y z | ψ