Metamath Proof Explorer


Theorem subcan2d

Description: Cancellation law for subtraction. (Contributed by Mario Carneiro, 22-Sep-2016)

Ref Expression
Hypotheses negidd.1 ⊢ φ → A ∈ ℂ
pncand.2 ⊢ φ → B ∈ ℂ
subaddd.3 ⊢ φ → C ∈ ℂ
subcan2d.4 ⊢ φ → A − C = B − C
Assertion subcan2d ⊢ φ → A = B

Proof

Step Hyp Ref Expression
1 negidd.1 ⊢ φ → A ∈ ℂ
2 pncand.2 ⊢ φ → B ∈ ℂ
3 subaddd.3 ⊢ φ → C ∈ ℂ
4 subcan2d.4 ⊢ φ → A − C = B − C
5 subcan2 ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ → A − C = B − C ↔ A = B
6 1 2 3 5 syl3anc ⊢ φ → A − C = B − C ↔ A = B
7 4 6 mpbid ⊢ φ → A = B