Metamath Proof Explorer


Theorem subrg0

Description: A subring always has the same additive identity. (Contributed by Stefan O'Rear, 27-Nov-2014)

Ref Expression
Hypotheses subrg0.1 S = R 𝑠 A
subrg0.2 0 ˙ = 0 R
Assertion subrg0 A SubRing R 0 ˙ = 0 S

Proof

Step Hyp Ref Expression
1 subrg0.1 S = R 𝑠 A
2 subrg0.2 0 ˙ = 0 R
3 subrgsubg A SubRing R A SubGrp R
4 1 2 subg0 A SubGrp R 0 ˙ = 0 S
5 3 4 syl A SubRing R 0 ˙ = 0 S