Metamath Proof Explorer


Theorem subsval

Description: The value of surreal subtraction. (Contributed by Scott Fenton, 3-Feb-2025)

Ref Expression
Assertion subsval ⊢ A ∈ No ∧ B ∈ No → A - s B = A + s + s ⁡ B

Proof

Step Hyp Ref Expression
1 oveq1 ⊢ x = A → x + s + s ⁡ y = A + s + s ⁡ y
2 fveq2 ⊢ y = B → + s ⁡ y = + s ⁡ B
3 2 oveq2d ⊢ y = B → A + s + s ⁡ y = A + s + s ⁡ B
4 df-subs ⊢ - s = x ∈ No , y ∈ No ⟼ x + s + s ⁡ y
5 ovex ⊢ A + s + s ⁡ B ∈ V
6 1 3 4 5 ovmpo ⊢ A ∈ No ∧ B ∈ No → A - s B = A + s + s ⁡ B