Metamath Proof Explorer


Theorem suceldifsn0

Description: A successor that is a member of a set is also a member of that set with the empty set removed. (Contributed by BTernaryTau, 19-Oct-2026)

Ref Expression
Hypotheses suceldifsn0.1 ⊢ A ∈ B
suceldifsn0.2 ⊢ A = suc ⁡ C
Assertion suceldifsn0 ⊢ A ∈ B ∖ ∅

Proof

Step Hyp Ref Expression
1 suceldifsn0.1 ⊢ A ∈ B
2 suceldifsn0.2 ⊢ A = suc ⁡ C
3 nsuceq0 ⊢ suc ⁡ C ≠ ∅
4 2 3 eqnetri ⊢ A ≠ ∅
5 eldifsn ⊢ A ∈ B ∖ ∅ ↔ A ∈ B ∧ A ≠ ∅
6 1 4 5 mpbir2an ⊢ A ∈ B ∖ ∅