Metamath Proof Explorer
Description: A successor that is a member of a set is also a member of that set with
the empty set removed. (Contributed by BTernaryTau, 19-Oct-2026)
|
|
Ref |
Expression |
|
Hypotheses |
suceldifsn0.1 |
⊢ 𝐴 ∈ 𝐵 |
|
|
suceldifsn0.2 |
⊢ 𝐴 = suc 𝐶 |
|
Assertion |
suceldifsn0 |
⊢ 𝐴 ∈ ( 𝐵 ∖ { ∅ } ) |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
suceldifsn0.1 |
⊢ 𝐴 ∈ 𝐵 |
| 2 |
|
suceldifsn0.2 |
⊢ 𝐴 = suc 𝐶 |
| 3 |
|
nsuceq0 |
⊢ suc 𝐶 ≠ ∅ |
| 4 |
2 3
|
eqnetri |
⊢ 𝐴 ≠ ∅ |
| 5 |
|
eldifsn |
⊢ ( 𝐴 ∈ ( 𝐵 ∖ { ∅ } ) ↔ ( 𝐴 ∈ 𝐵 ∧ 𝐴 ≠ ∅ ) ) |
| 6 |
1 4 5
|
mpbir2an |
⊢ 𝐴 ∈ ( 𝐵 ∖ { ∅ } ) |