Metamath Proof Explorer


Theorem sumeq12dv

Description: Equality deduction for sum. (Contributed by NM, 1-Dec-2005)

Ref Expression
Hypotheses sumeq12dv.1 ⊢ φ → A = B
sumeq12dv.2 ⊢ φ ∧ k ∈ A → C = D
Assertion sumeq12dv ⊢ φ → ∑ k ∈ A C = ∑ k ∈ B D

Proof

Step Hyp Ref Expression
1 sumeq12dv.1 ⊢ φ → A = B
2 sumeq12dv.2 ⊢ φ ∧ k ∈ A → C = D
3 2 sumeq2dv ⊢ φ → ∑ k ∈ A C = ∑ k ∈ A D
4 1 sumeq1d ⊢ φ → ∑ k ∈ A D = ∑ k ∈ B D
5 3 4 eqtrd ⊢ φ → ∑ k ∈ A C = ∑ k ∈ B D