Metamath Proof Explorer


Theorem syl5reqr

Description: An equality transitivity deduction. (Contributed by NM, 29-Mar-1998)

Ref Expression
Hypotheses syl5reqr.1 B = A
syl5reqr.2 φ B = C
Assertion syl5reqr φ C = A

Proof

Step Hyp Ref Expression
1 syl5reqr.1 B = A
2 syl5reqr.2 φ B = C
3 1 eqcomi A = B
4 3 2 syl5req φ C = A