Metamath Proof Explorer


Theorem syl5req

Description: An equality transitivity deduction. (Contributed by NM, 29-Mar-1998)

Ref Expression
Hypotheses syl5req.1 A = B
syl5req.2 φ B = C
Assertion syl5req φ C = A

Proof

Step Hyp Ref Expression
1 syl5req.1 A = B
2 syl5req.2 φ B = C
3 1 2 syl5eq φ A = C
4 3 eqcomd φ C = A