Metamath Proof Explorer


Theorem tgaascgra

Description: The comparison triangle of the AAS route: with H placed on ray E F at distance B C from E , the triangle D E H is congruent to A B C ( cgrahl2 then tgsas ), so its angle at H can be read off ( cgrcgra ) and matched against the given angle at F . The result is the angle congruence the case split of tgaas1h consumes. (Contributed by JAG, 12-Aug-2026)

Ref Expression
Hypotheses tgaascgra.p ⊢ P = Base G
tgaascgra.m ⊢ - ˙ = dist ⁡ G
tgaascgra.i ⊢ I = Itv ⁡ G
tgaascgra.l ⊢ L = Line 𝒢 ⁡ G
tgaascgra.k ⊢ K = hl 𝒢 ⁡ G
tgaascgra.g ⊢ φ → G ∈ 𝒢 Tarski
tgaascgra.a ⊢ φ → A ∈ P
tgaascgra.b ⊢ φ → B ∈ P
tgaascgra.c ⊢ φ → C ∈ P
tgaascgra.d ⊢ φ → D ∈ P
tgaascgra.e ⊢ φ → E ∈ P
tgaascgra.f ⊢ φ → F ∈ P
tgaascgra.h ⊢ φ → H ∈ P
tgaascgra.ncol ⊢ φ → ¬ C ∈ A L B ∨ A = B
tgaascgra.1 ⊢ φ → A - ˙ B = D - ˙ E
tgaascgra.2 ⊢ φ → ⟨“ ABC ”⟩ ∼ 𝒢 ∠ ⁡ G ⟨“ DEF ”⟩
tgaascgra.3 ⊢ φ → ⟨“ BCA ”⟩ ∼ 𝒢 ∠ ⁡ G ⟨“ EFD ”⟩
tgaascgra.4 ⊢ φ → H K ⁡ E F
tgaascgra.5 ⊢ φ → E - ˙ H = B - ˙ C
Assertion tgaascgra ⊢ φ → ⟨“ DFE ”⟩ ∼ 𝒢 ∠ ⁡ G ⟨“ DHE ”⟩

Proof

Step Hyp Ref Expression
1 tgaascgra.p ⊢ P = Base G
2 tgaascgra.m ⊢ - ˙ = dist ⁡ G
3 tgaascgra.i ⊢ I = Itv ⁡ G
4 tgaascgra.l ⊢ L = Line 𝒢 ⁡ G
5 tgaascgra.k ⊢ K = hl 𝒢 ⁡ G
6 tgaascgra.g ⊢ φ → G ∈ 𝒢 Tarski
7 tgaascgra.a ⊢ φ → A ∈ P
8 tgaascgra.b ⊢ φ → B ∈ P
9 tgaascgra.c ⊢ φ → C ∈ P
10 tgaascgra.d ⊢ φ → D ∈ P
11 tgaascgra.e ⊢ φ → E ∈ P
12 tgaascgra.f ⊢ φ → F ∈ P
13 tgaascgra.h ⊢ φ → H ∈ P
14 tgaascgra.ncol ⊢ φ → ¬ C ∈ A L B ∨ A = B
15 tgaascgra.1 ⊢ φ → A - ˙ B = D - ˙ E
16 tgaascgra.2 ⊢ φ → ⟨“ ABC ”⟩ ∼ 𝒢 ∠ ⁡ G ⟨“ DEF ”⟩
17 tgaascgra.3 ⊢ φ → ⟨“ BCA ”⟩ ∼ 𝒢 ∠ ⁡ G ⟨“ EFD ”⟩
18 tgaascgra.4 ⊢ φ → H K ⁡ E F
19 tgaascgra.5 ⊢ φ → E - ˙ H = B - ˙ C
20 1 3 6 5 8 9 7 11 12 10 17 cgracom ⊢ φ → ⟨“ EFD ”⟩ ∼ 𝒢 ∠ ⁡ G ⟨“ BCA ”⟩
21 1 3 4 6 7 8 9 14 tgbcne ⊢ φ → B ≠ C
22 1 3 4 6 7 8 9 14 tgacne ⊢ φ → A ≠ C
23 22 necomd ⊢ φ → C ≠ A
24 eqid ⊢ ∼ 𝒢 ⁡ G = ∼ 𝒢 ⁡ G
25 19 eqcomd ⊢ φ → B - ˙ C = E - ˙ H
26 1 3 5 6 7 8 9 10 11 12 16 13 18 cgrahl2 ⊢ φ → ⟨“ ABC ”⟩ ∼ 𝒢 ∠ ⁡ G ⟨“ DEH ”⟩
27 1 2 3 6 7 8 9 10 11 13 15 26 25 tgsas ⊢ φ → ⟨“ ABC ”⟩ ∼ 𝒢 ⁡ G ⟨“ DEH ”⟩
28 1 2 3 24 6 7 8 9 10 11 13 27 cgr3simp3 ⊢ φ → C - ˙ A = H - ˙ D
29 1 2 24 6 8 9 7 11 13 10 25 28 15 trgcgr ⊢ φ → ⟨“ BCA ”⟩ ∼ 𝒢 ⁡ G ⟨“ EHD ”⟩
30 1 3 6 5 8 9 7 11 13 10 21 23 29 cgrcgra ⊢ φ → ⟨“ BCA ”⟩ ∼ 𝒢 ∠ ⁡ G ⟨“ EHD ”⟩
31 1 3 6 5 11 12 10 8 9 7 20 11 13 10 30 cgratr ⊢ φ → ⟨“ EFD ”⟩ ∼ 𝒢 ∠ ⁡ G ⟨“ EHD ”⟩
32 1 3 2 6 11 12 10 11 13 10 31 cgraswaplr ⊢ φ → ⟨“ DFE ”⟩ ∼ 𝒢 ∠ ⁡ G ⟨“ DHE ”⟩