Metamath Proof Explorer
		
		
		
		Description:  Subclass relationship for subclass union.  Deduction form of uniss .
       (Contributed by David Moews, 1-May-2017)
		
			
				
					|  |  | Ref | Expression | 
					
						|  | Hypothesis | unissd.1 |  | 
				
					|  | Assertion | unissd |  | 
			
		
		
			
				Proof
				
					
						| Step | Hyp | Ref | Expression | 
						
							| 1 |  | unissd.1 |  | 
						
							| 2 |  | uniss |  | 
						
							| 3 | 1 2 | syl |  |