Metamath Proof Explorer


Theorem xoror

Description: Exclusive disjunction implies disjunction ("XOR implies OR"). (Contributed by BJ, 19-Apr-2019)

Ref Expression
Assertion xoror ⊢ φ ⊻ ψ → φ ∨ ψ

Proof

Step Hyp Ref Expression
1 xor2 ⊢ φ ⊻ ψ ↔ φ ∨ ψ ∧ ¬ φ ∧ ψ
2 1 simplbi ⊢ φ ⊻ ψ → φ ∨ ψ