Metamath Proof Explorer


Theorem xp2dju

Description: Two times a cardinal number. Exercise 4.56(g) of Mendelson p. 258. (Contributed by NM, 27-Sep-2004) (Revised by Mario Carneiro, 29-Apr-2015)

Ref Expression
Assertion xp2dju 2 𝑜 × A = A ⊔︀ A

Proof

Step Hyp Ref Expression
1 xpundir 1 𝑜 × A = × A 1 𝑜 × A
2 df2o3 2 𝑜 = 1 𝑜
3 df-pr 1 𝑜 = 1 𝑜
4 2 3 eqtri 2 𝑜 = 1 𝑜
5 4 xpeq1i 2 𝑜 × A = 1 𝑜 × A
6 df-dju A ⊔︀ A = × A 1 𝑜 × A
7 1 5 6 3eqtr4i 2 𝑜 × A = A ⊔︀ A