Metamath Proof Explorer


Theorem xpima1

Description: Direct image by a Cartesian product (case of empty intersection with the domain). (Contributed by Thierry Arnoux, 16-Dec-2017)

Ref Expression
Assertion xpima1 AC=A×BC=

Proof

Step Hyp Ref Expression
1 xpima A×BC=ifAC=B
2 iftrue AC=ifAC=B=
3 1 2 eqtrid AC=A×BC=