Metamath Proof Explorer


Theorem xpsff1o2

Description: The function appearing in xpsval is a bijection from the cartesian product to the indexed cartesian product indexed on the pair 2o = { (/) , 1o } . (Contributed by Mario Carneiro, 24-Jan-2015)

Ref Expression
Hypothesis xpsff1o.f ⊢ F = x ∈ A , y ∈ B ⟼ ∅ x 1 𝑜 y
Assertion xpsff1o2 ⊢ F : A × B ⟶ 1-1 onto ran ⁡ F

Proof

Step Hyp Ref Expression
1 xpsff1o.f ⊢ F = x ∈ A , y ∈ B ⟼ ∅ x 1 𝑜 y
2 1 xpsff1o ⊢ F : A × B ⟶ 1-1 onto ⨉ k ∈ 2 𝑜 if k = ∅ A B
3 f1of1 ⊢ F : A × B ⟶ 1-1 onto ⨉ k ∈ 2 𝑜 if k = ∅ A B → F : A × B ⟶ 1-1 ⨉ k ∈ 2 𝑜 if k = ∅ A B
4 f1f1orn ⊢ F : A × B ⟶ 1-1 ⨉ k ∈ 2 𝑜 if k = ∅ A B → F : A × B ⟶ 1-1 onto ran ⁡ F
5 2 3 4 mp2b ⊢ F : A × B ⟶ 1-1 onto ran ⁡ F