Metamath Proof Explorer


Theorem 0xp

Description: The Cartesian product with the empty set is empty. Part of Theorem 3.13(ii) of Monk1 p. 37. (Contributed by NM, 4-Jul-1994)

Ref Expression
Assertion 0xp ( ∅ × 𝐴 ) = ∅

Proof

Step Hyp Ref Expression
1 noel ⊢ ¬ 𝑥 ∈ ∅
2 simprl ⊢ ( ( 𝑧 = ⟨ 𝑥 , 𝑦 ⟩ ∧ ( 𝑥 ∈ ∅ ∧ 𝑦 ∈ 𝐴 ) ) → 𝑥 ∈ ∅ )
3 1 2 mto ⊢ ¬ ( 𝑧 = ⟨ 𝑥 , 𝑦 ⟩ ∧ ( 𝑥 ∈ ∅ ∧ 𝑦 ∈ 𝐴 ) )
4 3 nex ⊢ ¬ ∃ 𝑦 ( 𝑧 = ⟨ 𝑥 , 𝑦 ⟩ ∧ ( 𝑥 ∈ ∅ ∧ 𝑦 ∈ 𝐴 ) )
5 4 nex ⊢ ¬ ∃ 𝑥 ∃ 𝑦 ( 𝑧 = ⟨ 𝑥 , 𝑦 ⟩ ∧ ( 𝑥 ∈ ∅ ∧ 𝑦 ∈ 𝐴 ) )
6 elxpi ⊢ ( 𝑧 ∈ ( ∅ × 𝐴 ) → ∃ 𝑥 ∃ 𝑦 ( 𝑧 = ⟨ 𝑥 , 𝑦 ⟩ ∧ ( 𝑥 ∈ ∅ ∧ 𝑦 ∈ 𝐴 ) ) )
7 5 6 mto ⊢ ¬ 𝑧 ∈ ( ∅ × 𝐴 )
8 7 nel0 ⊢ ( ∅ × 𝐴 ) = ∅