Metamath Proof Explorer


Theorem 1stval2

Description: Alternate value of the function that extracts the first member of an ordered pair. Definition 5.13 (i) of Monk1 p. 52. (Contributed by NM, 18-Aug-2006)

Ref Expression
Assertion 1stval2 ( 𝐴 ∈ ( V × V ) → ( 1st ‘ 𝐴 ) = ∩ ∩ 𝐴 )

Proof

Step Hyp Ref Expression
1 elvv ⊢ ( 𝐴 ∈ ( V × V ) ↔ ∃ 𝑥 ∃ 𝑦 𝐴 = ⟨ 𝑥 , 𝑦 ⟩ )
2 vex ⊢ 𝑥 ∈ V
3 vex ⊢ 𝑦 ∈ V
4 2 3 op1st ⊢ ( 1st ‘ ⟨ 𝑥 , 𝑦 ⟩ ) = 𝑥
5 2 3 op1stb ⊢ ∩ ∩ ⟨ 𝑥 , 𝑦 ⟩ = 𝑥
6 4 5 eqtr4i ⊢ ( 1st ‘ ⟨ 𝑥 , 𝑦 ⟩ ) = ∩ ∩ ⟨ 𝑥 , 𝑦 ⟩
7 fveq2 ⊢ ( 𝐴 = ⟨ 𝑥 , 𝑦 ⟩ → ( 1st ‘ 𝐴 ) = ( 1st ‘ ⟨ 𝑥 , 𝑦 ⟩ ) )
8 inteq ⊢ ( 𝐴 = ⟨ 𝑥 , 𝑦 ⟩ → ∩ 𝐴 = ∩ ⟨ 𝑥 , 𝑦 ⟩ )
9 8 inteqd ⊢ ( 𝐴 = ⟨ 𝑥 , 𝑦 ⟩ → ∩ ∩ 𝐴 = ∩ ∩ ⟨ 𝑥 , 𝑦 ⟩ )
10 6 7 9 3eqtr4a ⊢ ( 𝐴 = ⟨ 𝑥 , 𝑦 ⟩ → ( 1st ‘ 𝐴 ) = ∩ ∩ 𝐴 )
11 10 exlimivv ⊢ ( ∃ 𝑥 ∃ 𝑦 𝐴 = ⟨ 𝑥 , 𝑦 ⟩ → ( 1st ‘ 𝐴 ) = ∩ ∩ 𝐴 )
12 1 11 sylbi ⊢ ( 𝐴 ∈ ( V × V ) → ( 1st ‘ 𝐴 ) = ∩ ∩ 𝐴 )