Metamath Proof Explorer


Theorem 1wlkdlem3

Description: Lemma 3 for 1wlkd . (Contributed by AV, 22-Jan-2021)

Ref Expression
Hypotheses 1wlkd.p ⊢ 𝑃 = ⟨“ 𝑋 𝑌 ”⟩
1wlkd.f ⊢ 𝐹 = ⟨“ 𝐽 ”⟩
1wlkd.x ⊢ ( 𝜑 → 𝑋 ∈ 𝑉 )
1wlkd.y ⊢ ( 𝜑 → 𝑌 ∈ 𝑉 )
1wlkd.l ⊢ ( ( 𝜑 ∧ 𝑋 = 𝑌 ) → ( 𝐼 ‘ 𝐽 ) = { 𝑋 } )
1wlkd.j ⊢ ( ( 𝜑 ∧ 𝑋 ≠ 𝑌 ) → { 𝑋 , 𝑌 } ⊆ ( 𝐼 ‘ 𝐽 ) )
Assertion 1wlkdlem3 ( 𝜑 → 𝐹 ∈ Word dom 𝐼 )

Proof

Step Hyp Ref Expression
1 1wlkd.p ⊢ 𝑃 = ⟨“ 𝑋 𝑌 ”⟩
2 1wlkd.f ⊢ 𝐹 = ⟨“ 𝐽 ”⟩
3 1wlkd.x ⊢ ( 𝜑 → 𝑋 ∈ 𝑉 )
4 1wlkd.y ⊢ ( 𝜑 → 𝑌 ∈ 𝑉 )
5 1wlkd.l ⊢ ( ( 𝜑 ∧ 𝑋 = 𝑌 ) → ( 𝐼 ‘ 𝐽 ) = { 𝑋 } )
6 1wlkd.j ⊢ ( ( 𝜑 ∧ 𝑋 ≠ 𝑌 ) → { 𝑋 , 𝑌 } ⊆ ( 𝐼 ‘ 𝐽 ) )
7 1 2 3 4 5 6 1wlkdlem2 ⊢ ( 𝜑 → 𝑋 ∈ ( 𝐼 ‘ 𝐽 ) )
8 elfvdm ⊢ ( 𝑋 ∈ ( 𝐼 ‘ 𝐽 ) → 𝐽 ∈ dom 𝐼 )
9 s1cl ⊢ ( 𝐽 ∈ dom 𝐼 → ⟨“ 𝐽 ”⟩ ∈ Word dom 𝐼 )
10 2 9 eqeltrid ⊢ ( 𝐽 ∈ dom 𝐼 → 𝐹 ∈ Word dom 𝐼 )
11 7 8 10 3syl ⊢ ( 𝜑 → 𝐹 ∈ Word dom 𝐼 )