Metamath Proof Explorer


Theorem 3com12d

Description: Commutation in consequent. Swap 1st and 2nd. (Contributed by Jeff Hankins, 17-Nov-2009)

Ref Expression
Hypothesis 3com12d.1 ⊢ ( 𝜑 → ( 𝜓 ∧ 𝜒 ∧ 𝜃 ) )
Assertion 3com12d ( 𝜑 → ( 𝜒 ∧ 𝜓 ∧ 𝜃 ) )

Proof

Step Hyp Ref Expression
1 3com12d.1 ⊢ ( 𝜑 → ( 𝜓 ∧ 𝜒 ∧ 𝜃 ) )
2 id ⊢ ( ( 𝜒 ∧ 𝜓 ∧ 𝜃 ) → ( 𝜒 ∧ 𝜓 ∧ 𝜃 ) )
3 2 3com12 ⊢ ( ( 𝜓 ∧ 𝜒 ∧ 𝜃 ) → ( 𝜒 ∧ 𝜓 ∧ 𝜃 ) )
4 1 3 syl ⊢ ( 𝜑 → ( 𝜒 ∧ 𝜓 ∧ 𝜃 ) )