Metamath Proof Explorer
		
		
		
		Description:  Commutation in consequent.  Swap 1st and 2nd.  (Contributed by Jeff
       Hankins, 17-Nov-2009)
		
			
				
					|  |  | Ref | Expression | 
					
						|  | Hypothesis | 3com12d.1 | ⊢ ( 𝜑  →  ( 𝜓  ∧  𝜒  ∧  𝜃 ) ) | 
				
					|  | Assertion | 3com12d | ⊢  ( 𝜑  →  ( 𝜒  ∧  𝜓  ∧  𝜃 ) ) | 
			
		
		
			
				Proof
				
					
						| Step | Hyp | Ref | Expression | 
						
							| 1 |  | 3com12d.1 | ⊢ ( 𝜑  →  ( 𝜓  ∧  𝜒  ∧  𝜃 ) ) | 
						
							| 2 |  | id | ⊢ ( ( 𝜒  ∧  𝜓  ∧  𝜃 )  →  ( 𝜒  ∧  𝜓  ∧  𝜃 ) ) | 
						
							| 3 | 2 | 3com12 | ⊢ ( ( 𝜓  ∧  𝜒  ∧  𝜃 )  →  ( 𝜒  ∧  𝜓  ∧  𝜃 ) ) | 
						
							| 4 | 1 3 | syl | ⊢ ( 𝜑  →  ( 𝜒  ∧  𝜓  ∧  𝜃 ) ) |