Metamath Proof Explorer


Theorem 3eltr4g

Description: Substitution of equal classes into membership relation. (Contributed by Mario Carneiro, 6-Jan-2017) (Proof shortened by Wolf Lammen, 23-Nov-2019)

Ref Expression
Hypotheses 3eltr4g.1 ⊢ ( 𝜑 → 𝐴 ∈ 𝐵 )
3eltr4g.2 ⊢ 𝐶 = 𝐴
3eltr4g.3 ⊢ 𝐷 = 𝐵
Assertion 3eltr4g ( 𝜑 → 𝐶 ∈ 𝐷 )

Proof

Step Hyp Ref Expression
1 3eltr4g.1 ⊢ ( 𝜑 → 𝐴 ∈ 𝐵 )
2 3eltr4g.2 ⊢ 𝐶 = 𝐴
3 3eltr4g.3 ⊢ 𝐷 = 𝐵
4 2 1 eqeltrid ⊢ ( 𝜑 → 𝐶 ∈ 𝐵 )
5 4 3 eleqtrrdi ⊢ ( 𝜑 → 𝐶 ∈ 𝐷 )