Theorem 6p5e11

Description: 6 + 5 = 11. (Contributed by Mario Carneiro, 19-Apr-2015) (Revised by AV, 6-Sep-2021)

	Ref	Expression
Assertion	6p5e11	⊢ ( 6 + 5 ) = ; 1 1

Proof

Step	Hyp	Ref	Expression
1		6nn0	⊢ 6 ∈ ℕ0
2		4nn0	⊢ 4 ∈ ℕ0
3		0nn0	⊢ 0 ∈ ℕ0
4		df-5	⊢ 5 = ( 4 + 1 )
5		1e0p1	⊢ 1 = ( 0 + 1 )
6		6p4e10	⊢ ( 6 + 4 ) = ; 1 0
7	1 2 3 4 5 6	6p5lem	⊢ ( 6 + 5 ) = ; 1 1