Metamath Proof Explorer


Theorem 6p5e11

Description: 6 + 5 = 11. (Contributed by Mario Carneiro, 19-Apr-2015) (Revised by AV, 6-Sep-2021)

Ref Expression
Assertion 6p5e11 ⊢ 6 + 5 = 11

Proof

Step Hyp Ref Expression
1 6nn0 ⊢ 6 ∈ ℕ 0
2 4nn0 ⊢ 4 ∈ ℕ 0
3 0nn0 ⊢ 0 ∈ ℕ 0
4 df-5 ⊢ 5 = 4 + 1
5 1e0p1 ⊢ 1 = 0 + 1
6 6p4e10 ⊢ 6 + 4 = 10
7 1 2 3 4 5 6 6p5lem ⊢ 6 + 5 = 11